The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

As we know the ratio of the sides is 3:4:5, label the sides x,y and z respectively. Side x is of length (3/12)*72, side y is of length (4/12)*72 and side z is of length (5/12)72. Giving, x = 18cm, y = 24cm, z = 30cm. Observe x is the base and z is the hypotenuse. Area of a triangle is (base x height)/2. Area = (1824)/2 = 216cm^2

VS
Answered by Viresh S. Maths tutor

2990 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is Pythagoras' Theorem and how do I use it?


Solve the equation: x^2 - 9x + 20 = 0


Find g(f(x)) where g(x)=2x+4 and f(x)=x^2+1.


Write the equation x^2 + 6x - 40 = 0 in the form (x + a)^2 - b = 0 and then solve for x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning