This question is dealing with phenomena of Redshift, where wavelengths are shifted due to movement between observer and event. The key information to extract from the question is we have a rest wavelength, an observed wavelength and want a velocity of the galaxy (relative to Earth) from where the light has come from. The observed wavelength is larger than the rest wavelength -> wavelength is increased meaning that the galaxy is moving away, hence the question asks for a recessional velocity . So we should expect a positive velocity as our answer.The formula for redshift is given in the higher formula sheet as Z = (λobs - λrest) / λrestAlso given is Z = V/c , where c is the speed of light. We want to solve for V, as this is the recessional velocity, both equations are equal to Z, so we can equate, meaning :V/c = (λobs - λrest) / λrest -> timesing both sides by c, we get an expression for V in terms of everything we know! V = c(λobs - λrest) / λrest -> c = 3 x 108 m/s , λobs = 656nm , λrest = 661nm (as both rest and obs are in nm we don't need to worry about converting to metres as we calculating a ration) V = 3 x 108 (661-656) / 656 ≈ 2.29 x 106 m/s (always remember units are part of the answer too!)