Solve the simultaneous equations 2x + 3y = 4, 3x + 6y = 3

Label the equations (1): 2x + 3y = 4 (2): 3x + 6y = 3We need the same number of x's or y's in the equations, so multiply (1) by 3 and (2) by 2 giving (3): 6x + 9y = 12 (4): 6x + 12y = 6Subtract (3) from (4) 6x + 12y - 6x - 9y = 6 - 12 so 3y= -6 so y= -2Substitute the y value into (1) to find x 2x + (3*-2) = 4    2x - 6 = 4       2x = 10        x = 5Check by substituting into (2) (35) + (6-2) = 15 - 12 = 3 the solutions workSo x = 5 and y = -2

Answered by Sophie S. Maths tutor

9125 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Issy goes to buy some fruit. She has been told by one friend that 2 apples and 3 bananas costs £3.80. She has been told by another friend that 5 apples and a banana costs £3.65. what are the individual costs of an apple and a banana?


Solve the two simultaneous equations y+5x=30 and 6y=-x+64


how do you work out the gradient and point of interception of a linear graph given some coordinates


Solve x2 +2x – 4 = 0, leaving your answer in simplest surd form (4 marks, non calculator question)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences