Solve the quadratic equation x^2 + x - 20 = 0

Factorising the left hand side we get x2 + x - 6 = (x + 5)(x - 4). Therefore x2 + x - 6 = 0 is the same as (x + 5)(x - 4) = 0. If multiplying two quantities equals 0, this means that one of the two must equal 0. This means (x +5) = 0 or (x - 4) = 0, therefore x + 5 = 0, gives x= -5 or x - 4 =0, gives x = 4 (using the inverse operation).
Therefore, there are two solutions, x= -5 and x=4

Answered by Lizlie J. Maths tutor

2835 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The equation of the line L1 is y = 3x – 2 The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel.


How do you simplify (3x-3)/(x-1)?


Solve the simultaneous equations; 2x + y = 18; x + 3y = 19.


Consider f:R -> R, f = x/ sqrt(x^2+1). Prove that for any a between -1 and 1, f(x)=a has only one solution.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences