a) Factorise: 2x^2-72, and hence b) find the y-intercept of the line with the equation: y=(2x^2-72)/(4x-24)

a) Take out the common factor, giving: 2(x2-36), idenitfy the difference of two squares and factoise accordingly, giving: 2(x-6)(x+6)
b) you have the facotirse version of the top of the fraction from part a), factorise the bottom, giving: 4(x-6), then cancel and simplify, giving: y=1/2x+3
Then let x=0 to find the y-intercept to be when y=3

IS

Related Maths Scottish Highers answers

All answers ▸

Point K(8,-5) lies on the circle x^2 +y^2 - 12x - 6y - 23. find the equation of the tangent at K.


Given that dy/dx = 6x*2 - 3x + 4 And y =14 when x=2. Express y in terms of x


Solve algebraically the system of equations: 4x+5y=-3 and 6x-2y=5


A circle has equation x^2+y^2-8x+10y+41=0. A point on the circle has coordinates (8,-3). Find the equation of the tangent to the circle passing through this point.