a) Factorise: 2x^2-72, and hence b) find the y-intercept of the line with the equation: y=(2x^2-72)/(4x-24)

a) Take out the common factor, giving: 2(x2-36), idenitfy the difference of two squares and factoise accordingly, giving: 2(x-6)(x+6)
b) you have the facotirse version of the top of the fraction from part a), factorise the bottom, giving: 4(x-6), then cancel and simplify, giving: y=1/2x+3
Then let x=0 to find the y-intercept to be when y=3

IS

Related Maths Scottish Highers answers

All answers ▸

dy/dx = 6x^2 - 3x + 4 when y=14 x=2 Find y in terms of x


log_a(36) - log_a(4) = 0.5, what is a?


Find the x-coordinates of the stationary points on the graph with equation f(x)= x^3 + 3x^2 - 24x


How do you solve integrals which are the result of a chain rule e.g. the integral of sin(2x+1)