Find dy/dx when y=(3x-1)^10
We have to use the chain rule in this instance to find the differentiated value y=(3x-1)^10 suppose y=u^10 thus, dy/du = 10u^9 secondly: u=3x-1 du/dx=3 the chain rule suggests that dy/dx = du/dx *dy/du so that du cancels out Therefore, dy/dx = 10(3x-1)^9 * (3)Simplified, dy/dx = 30(3x-1)^9
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