y(x) = x^2(1-x)e^-2x , find y'(x) in the form of g(x)e^-2x where g(x) is a cubic function to be found

For this question, I would first expand the brackets in the given y(x) to form , x^2e^-2x -x^3e^-2x . With this form, I would then differeniate using the chain rule to then obtain the expression that can easily be put in the form of g(x)e^-2x

Answered by Arjun B. Maths tutor

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