Find the 4th roots 6

Express 6 in the exponential form of (6*exp(2πin)), where n is an integertake the fourth root of this, remembering that taking the fourth root is taking to the power of 1/4, and by rules of indices the expression in the exponent must be divided by 4This gives (61/4 *exp(πin/2))Taking n = 0,1,2,3 gives four distinct roots, any larger n gives repeated roots

NP

Related Further Mathematics A Level answers

All answers ▸

Prove that ∑(1/(r^2 -1)) from r=2 to r=n is equal to (3n^2-n-2)/(4n(n+1)) for all natural numbers n>=2.


Using de Moivre's theorem demonstrate that "sin6x+sin2x(16(sinx)^4-16(sinx)^2+3)"


Integrate xcos(x) with respect to x


Solve for z in the equation sin(z) = 2