A piece of card is released from rest at a height of 0.5m above a light gate. It falls freely and a computer measures the velocity as it passes through the light gate to be 3.10m/s. What is the acceleration due to gravity measured by this experiment?

This question can be solved using suvat equations, since the acceleration due to gravity is constant. First make a list of the variables given in the question;

s=0.5m

u=0ms-1 (since the card is released from rest)

v=3.1ms-1

a=?

We can then select a suvat equation containing these variables, which we can use to solve the problem. In this case we choose v2=u2+2as, as this contains only one unknown (a). Substituting the variables in, we get;

3.12=02+2a(0.5)

This simplifies to;

3.12=a

So the acceleration due to gravity measured in this experiment is 9.61ms-2.

HC
Answered by Hannah C. Physics tutor

1721 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Describe how a PET scan works?


A circuit with a voltage source of 18V, has 3 resistors all connected on parallel, values at 2ohms, 6ohms and 7.5ohms. Find the total circuit resistance, and then subsequently, the total current supplied and power dissipated in the curcuit.


How would you explain general relativity?


A car undergoes uniform acceleration from a starting velocity of 10ms^-1 to 20ms^-1 in 10s. Assuming the car's mass is 2000kg, calculate the net force in the direction of the acceleration.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences