f(x) = (sin(x))^3. What is f'(x)
Write sin3(x) as sin2x*sinx and differentiate using product rule, u=sin2x, v=sinx, du/dx=2sinxcosx, dv/dx=cosx where the product rule is u(dv/dx) + v(du/dx). This gets 2sin2xcosx + sin2xcosx = 3sin2xcosx which is the correct answer
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