Where does the geometric series formula come from?

Rearranging the terms of the series into the usual "descending order" for polynomials, we get a series expansion of:  

axn-1 +........ax + a

A basic property of polynomials is that if you divide xn – 1 by x – 1, you'll get:

xn–1 + xn–2 + ... + x3 + x2 + x + 1

That is: 

a(xn–1 + xn–2 + ... + x3 + x2 + x + 1) = a(xn-1)/(x-1)

The above derivation can be extended to give the formula for infinite series, but requires tools from calculus. For now, just note that, for | r | < 1, a basic property of exponential functions is that rn must get closer and closer to zero as n gets larger. Very quickly, rn is as close to nothing as makes no difference, and, "at infinity", is ignored. This is, roughly-speaking, why the rn is missing in the infinite-sum formula.

NA
Answered by Naheem A. Maths tutor

4741 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How can I find all the solutions to cos(3x) = sqrt(2)/2 for 0<=x<=2pi ?


How do you integrate ln(x)?


Find dy/dx when y = 5x^6 + 4x*sin(x^2)


Prove algebraically that the sum of the squares of two consecutive multiples of 5 is not a multiple of 10.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning