Express 5/(2-sqrt(3)) in the form a + b*sqrt(3)

The first step that needs to be taken is to get rid of the square root from the denominator. This can be done by multiplying the top and bottom of the fraction by 2 + sqrt(3). This gives (10 + 5sqrt(3))/(4-3) = 10 + 5sqrt(3). This gives the answer in the desired form with a as 10 and b as 5.

Answered by Guy V. Maths tutor

10275 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is the gradient of the line passing through the point (1,2) and (5,5)? What is the equation of this line? What is the equation of the line perpendicular to this line that passes through the origin (0,0)?


Use BIDMAS to answer 2 + 7 x 10


Simply fully (3x^2 - 8x - 3) / 2x^2 - 6x


A and B are points on a circle, centre O. BC is a tangent to the circle. AOC is a straight line. Angle ABO = x°. Find the size of angle ACB, in terms of x. Give your answer in its simplest form. Give reasons for each stage of your working.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences