How to differentiate y=2x(x-2)^5 to find dy/dx?

Firstly, you should formulate the problem by using the product rule, which is: dy/dx = u'v + v'uBy assigning u=2x and v=(x-2)5 , the terms u' and v' can be obtained knowing that u' simply means differentiation of u with respect to x and v' is the differential of v with respect to x.u' = 2;v' = 51(x-2)^4Combining the terms, dy/dx = 2(x-2)5 + 10x(x-2)4 which is in its simplest form and provides the answer for subsequent question parts.

AP

Related Maths A Level answers

All answers ▸

If a circle passes through points (2,0) and (10,0) and it has tangent line along the y-axis, then what are the possible equations of the circle?


Why does the product rule for differentiating functions work?


Find dy/dx of the equation y=x^2 ln⁡(2x^2+1).


Differentiate with respect to x: x*cos(x)