How to differentiate y=2x(x-2)^5 to find dy/dx?

Firstly, you should formulate the problem by using the product rule, which is: dy/dx = u'v + v'uBy assigning u=2x and v=(x-2)5 , the terms u' and v' can be obtained knowing that u' simply means differentiation of u with respect to x and v' is the differential of v with respect to x.u' = 2;v' = 51(x-2)^4Combining the terms, dy/dx = 2(x-2)5 + 10x(x-2)4 which is in its simplest form and provides the answer for subsequent question parts.

AP
Answered by Anup P. Maths tutor

5993 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

f(x)= 2x^3 -7x^2 + 2x +3. Given that (x-3) is a factor of f(x), express f(x) in a fully factorised form.


Solve the Equation: 2ln(x)−ln (7x)=1


Find the solutions of the equation 3cos(2 theta) - 5cos(theta) + 2 = 0 in the interval 0 < theta < 2pi.


Find dy/dx of the equation y=x^2 ln⁡(2x^2+1).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning