How would you solve (4y + 3)/5 + (3y+1)/2 = 4 for y?

The first step is to remove the fractions in the equation, as the equation is easier to solve when there are only whole numbers.To remove the first fraction we should times the entire equation by 5 ----> 4y + 3 + 15y+5)/2 = 20 <-- It is important to remember to times both sides of the equation - students tend to forget this!To remove the second fraction we should times the entire equation by 2 ---> 8y + 6 + 15y + 5 = 40The next step is to move all the y's to one side and all the numbers to the other side ---> 23y = 40 - 6 - 5 ---> 23y=29Now that we know what 23y is equal to, to find out what y is equal to we must divide 29 by 23Therefore y = 29/23

Answered by Nima S. Maths tutor

2242 Views

See similar Maths KS3 tutors

Related Maths KS3 answers

All answers ▸

A piece of wire is 240cm long. Peter cuts two 45 cm lengths off the wire. He then cuts the rest of the wire into as many 40cm length as possible. How many wires of 40cm can be cut?


Use Pythagoras theorem to work out the hypotenuse when the adjacent length of a triangle is 3 and the opposite side is 4.


Find the value of 'a' in the equation: 5a + 12 = 37


Solve the following algebraic equation: x^2 + 6x + 9 = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences