Solve the simultaneous equations: x + 2y = 13, 4x - 3y = 8.

Multiply both sides of the equation x + 2y = 13 by 4 to get 4x + 8y = 52. Subtract 4x - 3y = 8 from 4x + 8y = 52 to get 11y = 44. Divide both sides of 11y = 44 by 11 to get y = 4. Since we now know y = 4, we can replace y with 4 in the equation x + 2y = 13 to get x + 8 = 13. Rearranging that to make x the subject of the formula results in x = 13 - 8 = 5, therefore the solution to the equations are x = 5, y = 4.

KP
Answered by Kate P. Maths tutor

5582 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Work out (2^34) / (2^3)^10


3x + y = -4; 3x -4y = 6; Solve the simultaneous equations for x and y


How do you factorise a quadratic equation where the coefficient of x² isn't 1?


Work out ∛16 as a power of two. (AQA GCSE Higher paper 2017, Q24b)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning