The sides of an equilateral triangle are given by the expressions x+y, 2y-1 and 3y-2x+1. Find the values of x and y.

This question test knowledge of the geometry of equilateral triangles and the students ability to solve linear equations.
First we note that an equilateral triangle has equal sides. Then we can write that x+y = 2y-1 and rearranging we find that x = y-1. Further we know that 2y-1 = 3y-2x+1 and rearranging we find that y = 2x -2. We then substitute this into the first equation we found so that x = (2x-2)-1 and rearranging once again we find that x = 3. Substituting this into y = 2x-2, we find that y = 4.

Answered by Joe S. Maths tutor

5873 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Make x the subject of the equation. (x + y)/ 9 = 2x


complete the square by rewriting x^2+6x-15 in the form (x+p)^2-q


Prove that the product of 3 consecutive integers is divisible by 6


Write the equation x^2 + 6x - 40 = 0 in the form (x + a)^2 - b = 0 and then solve for x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences