A is the point (2,-5), B is the point (-1,4). (a) What is the gradient of the line passing through points A and B? (b) Does the point (-100,301) lie on the line passing through points A and B?

(a) let A be (x1,y1) and B be (x2,y2), Gradient = m = (y2-y1)/(x2-x1) m = (4- -5)/(-1-2) = 9/(-3) = -3 Gradient = -3
(b) equation of a straight line line: y = mx + c => y1 = m(x1) + c -5 = -3(2) + c c = -5 +6 = 1=> Equation of line through A and B: y = -3x +1at (-100, 301), x = -100 => y = -3(-100) + 1 = 301 (from equation of line)Therefore this point does lie on the line

Answered by Hallam M. Maths tutor

2914 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the equation 3x^(2)-7x+3 giving your answer to three significant figures.


Pythagoras: If you have a right angled triangle PQR, and length PQ=5cm, length QR=8cm (which is the longest length), then calculate length PR to two decimal places.


You are told that a straight line runs through 2 points: (1,1) and (2,3). What is the equation of the line?


Quadratic equation


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences