Solve the two simultaneous equations y+5x=30 and 6y=-x+64

The easiest way to solve these equations is by substitution. Rearrange the 6y=-x+64 equation into the form of x=64-6y. Replace x in the other equation with x=64-6y to produce y+5(64-6y)=30. Multiply out the brackets and rearrange to produce -29y=-290 so y=10. Substitute y=10 into the equation x=64-6y to get x=64-60 so x=4. 

Answered by Harriet W. Maths tutor

2468 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

I find the percentage questions really hard, how do I answer the questions that will come up in exams?


Solve 3x - 5 < 16


Kenny has £3200 in a savings account. After a year, the bank pays him interest increasing his balance to £3360. What percentage rate was applied to the account?


A straight line goes through (0,1), (2,5) and (4,9). The equation of the straight line is y=2x+1. Is the point (7,12) on this straight line?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences