Find max point of y=-x^2-5x-10

Can either differentiate or using the completing the square method. Differentiation not covered at GCSE so completing the square should be done to get -((x+5/2)2+15/4). To find the max point we need to find the minimum value of (x+5/2)2. This is 0 (due to square) which occurs when x=-5/2 in which case y=-15/4. This can easily be done by equating the x value to the negative of the value within the inner bracket and y value to the value in the outer bracket.

Answered by Gautham R. Maths tutor

2835 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2+3x-18=0 for x


C is a circle with equation x^2 + y^2 = 16. The point P = (3,√7) is on C. Find the equation of the tangent to C at the point P.


How do I solve a simple simultaneous equation?


How do you find the volume of a cylinder?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences