If -3x + 10y = -100 and 13x + 10y = 60, solve for x and y.

This can be solved simultaneously. This is about manipulating the equations until they're in a format that you can use.Label the equations:eq1: -3x + 10y = -100 and eq2: 13x + 10y = 60Now, eq1 - eq2 gives us -16x + 0y = -160. The y's have cancelled out. The manipulation should always first try to remove one of the unknowns.-16x = -160, so we can remove the minus signs.x = 160/16 = 10.We can now sub x into one of the original equations. Let's use eq2.13x + 10y = 6013(10) + 10y = 60130 +10y =6010y = 60 - 130 = 70y = -70/10 = -7Therefore, x = 10, y = -7

Answered by Olyvia J. Maths tutor

2849 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that the square of an odd number is always 1 more than a multiple of 4


Billy buys 4 adult tickets at £15 each and 2 child tickets at £10 each for show. A 10% booking fee is added to the ticket price. 3% is then added for paying by credit card. Find the total charge for these tickets when paying by card


Finding the value of x when 3x + 5 = 35


Solve the following simultaneous equations to find the values of x and y: 3y - 7x = 15 & 2y = 4x + 12


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences