If -3x + 10y = -100 and 13x + 10y = 60, solve for x and y.

This can be solved simultaneously. This is about manipulating the equations until they're in a format that you can use.Label the equations:eq1: -3x + 10y = -100 and eq2: 13x + 10y = 60Now, eq1 - eq2 gives us -16x + 0y = -160. The y's have cancelled out. The manipulation should always first try to remove one of the unknowns.-16x = -160, so we can remove the minus signs.x = 160/16 = 10.We can now sub x into one of the original equations. Let's use eq2.13x + 10y = 6013(10) + 10y = 60130 +10y =6010y = 60 - 130 = 70y = -70/10 = -7Therefore, x = 10, y = -7

Answered by Olyvia J. Maths tutor

2733 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations: 4x + 5y = -8 and 6x-2y = 26


A 4kg bag of rice costs £3.20 and a 6kg bag of rice costs £5.80. Which bag of rice is the best value for money? Show all your working.


A particle is moving along a straight line. The fixed point O lies on this line. The displacement of the particle from O at time t seconds is s metres where s = 2t3 – 12t2 + 7t(a) Find an expression for the velocity, v m/s, of the particle at time t.


y is inversely proportional to x. y = 0.04 when x = 80. Find the value of y when x = 32.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences