A box contains 7 caramel doughnuts. They have masses of 56 g, 67 g, 45 g, 56 g, 58 g, 49 g and 50 g. Find the median, mean and mode values of these masses. Bonus: What mass of doughnut could be added to the box to make the mean mass = 61 g.

Median: Order the values from lowest to highest: 45, 49, 50, 56, 56, 58, 67. Pick the middle value. Answer = 56 g.Mode: The most common value. Answer = 56 g.Mean: Add all the values up, then divide the result by the number of values: 45 + 49 + 50 + 56 + 56 + 58 + 67 = 381, then 381 / 7 = 54.4 g. You could round this to 54 g, because the other numbers are given to 0 decimal places (or also to 2 significant figures.). Answer = 54 g.
Bonus:Calculate the mean in reverse. So 61 X 7 = 427, then 427 - 45 - 49 - 50 - 56 - 56 - 58 - 67 = 46 g. Answer = 46 g.

KG

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations to find x and y: 3x + 5y = 10 , 5x + 4y = 8


How do I multiply two brackets without missing terms when multiplying?


What is a vector and how do I calculate the 'modulus' of a vector?


Clare buys some shares for $50x. Later, she sells the shares for $(600 + 5x). She makes a profit of x% (a) Show that x^2 + 90x − 1200 = 0