How do you take the derivative of a^x ?

There are two ways you can take the derivative of a^x.
1) 
Let y = a^x  now we're trying to find dy/dx
2)
ln(y) = xln(a)  take logs of both sides and use log rules
3)
(dy/dx)*(1/y) = ln(a) take the derivative of both sides using the chain rule                     on the left hand side.
4)
dy/dx = ln(a)*y       multiply both sides by y
5)
dy/dx = ln(a) *a^x    realise y= a^x and replace it
Now we're done!
 
Alternatively we could realise that any exponent can be written as e to the power of something with a log in it.
So
1)
y = a^x = (e^ln(a))^x  just rewritting 'a'
2)
y = e^xln(a)        multiplying exponent rule
3)
dy/dx = ln(a)*e^xln(a) take the derivative of both sides using the chain                         rule for the right hand side
4)
dy/dx = ln(a)*a^x            substitute back to get desired result
 
 
 

Answered by Sam G. Maths tutor

5594 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate 7(3x^2+7)^(1/3)


A sequence is defined as: U(n+1) = 1/U(n) where U(1)=2/3. Find the sum from r=(1-100) for U(r)


Find dy/dx in terms of t for the curve defined by the parametric equations: x = (t-1)^3, y = 3t - 8/t^2, where t≠0


(a) By using a suitable trigonometrical identity, solve the equation tan(2x-π/6)^2 =11-sec(2x-π/6)giving all values of x in radians to two decimal places in the interval 0<=x <=π .


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences