A particle is moving in a straight line from A to B with constant acceleration 4m/s^2. The velocity of the particle at A is 3m/s in the direction AB. The velocity of the particle at B is 18m/s in the same direction/ Find the distance from A to B.

First draw a diagram to see the set-up.Then look at SUVAT to see which values we have been given. In this case it is a=4, u=3,v=18 and s=?. The only letter not used from SUVAT is the t so we use the formula without... v²=u²+2as. Fill in the numbers 18²=3²+2 x 4 x s324 = 9+ 8s. Rearranges = (324-9)/8 = 39.375 m