First factorise the quadratic: (2x + 1)(x + 3). Next set the factorised equation to 0: (2x + 1)(x + 3) = 0. Then solve the equation to find the 2 values of x, dividing through one bracket at a time: First dividing through by (x + 3): x = -(1/2). Then dividing through by (2x + 1): x = -3