Solve ((x+2)/3x) + ((x-2)/2x) = 3

Multiple first fraction through by 2 and second fraction through by 3((2x+4)/6x) + ((3x-6)/6x) = (5x-2)/(6x) = 3Expand brackets and isolate x5x-2 = 18x13x = -2x = -2/13

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Given: 𝑓(π‘₯) = π‘Žπ‘₯^3 + 𝑏π‘₯^2 βˆ’ 3 and 𝑓"(βˆ’2) = 0. If it is further given that the point (βˆ’3; 6) lies on the graph of 𝑓. Show that π‘Ž = 1/3 and 𝑏 = 2.


v^2 = u^2 + 2as u = 12 a = –3 s = 18 (a) Work out a value of v. (b) Make s the subject of v^2 = u^2 + 2as


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