A linear sequence starts a + 2b, a +6b, a + 10b. The 2nd has a value of 8 and the 5th term has a value of 44. What are the values of a and b?

a + 6b = 8 5th term: a + 18b = 44
term 1: a + 6b = 8term 2: a + 18b = 44
term 2 - term 1: 12b = 36b = 36/12 = 3
a + 6b = 8a + 6(3) = 8a = 8-18 = -10

Answered by Leonie R. Maths tutor

2992 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A car costs £1200 in a sale. It was reduced by 20%. What was the original price?


How do I use Pythagorus' Theorum?


Solve the simultaneous equations '2X+Y=7' and '3X-Y=8'


In a class there are 57 students. Of these 32 study Spanish, 40 study German and 12 students study neither. How many students study Spanish but not German?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences