A linear sequence starts a + 2b, a +6b, a + 10b. The 2nd has a value of 8 and the 5th term has a value of 44. What are the values of a and b?

a + 6b = 8 5th term: a + 18b = 44
term 1: a + 6b = 8term 2: a + 18b = 44
term 2 - term 1: 12b = 36b = 36/12 = 3
a + 6b = 8a + 6(3) = 8a = 8-18 = -10

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Answered by Leonie R. Maths tutor

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