Given that x = i is a solution of 2x^3 + 3x^2 = -2x + -3, find all the possible solutions

x = i is a solution, and all the coefficients are real, so x = -i must also be a solution:2x^3+3x^2+2x+3 = 0(x+i)(x-i)(Ax+B) = 0 (we argued above that this must be the case)(x^2+1)(Ax+B) = 0(x^2+1)(2x+3) = 0 (we identify A and B by comparing to the first line)Therefore x = -3/2 is the third solution, and we have all the solutions

Related Further Mathematics A Level answers

All answers ▸

Find the values of x where x+3>2/(x-4), what about x+3>2/mod(x-4)?


write 2-2i in its modulus argument form


Find the general solution of y'' - 3y' + 2y = 2e^x


How do I find the square root of a complex number?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences