Answers>Maths>A Level>Article

The numbers a, b, c and d satisfy the following equations: a + b + 3c + 4d = k; 5a = 3b = 2c = d. What is the smallest value for k for which a, b, c and d are all positive integers

  1. 5a = 3b = 2c = d. d must be a multiple of 5, 3 and 2, therefore the smallest possible value for d is 30. This sets a = 6, b = 10 and c = 152) a + b + 3c + 4d = 6 + 10 + 3x15 + 4x30 = 181 k = 181
MH

Related Maths A Level answers

All answers ▸

A circle with equation x^2+y^2-2x+8y-40=0. Find the circle centre and the radius

Liam M. avatarAnswered by Liam M.

Differentiate xcos(x) with respect to x.

Oliver S. avatarAnswered by Oliver S.

Express 2cos(x) + 5sin(x) in the form Rsin(x + a) where 0<a<90

Dan H. avatarAnswered by Dan H.

Write sqrt(50) in the form Asqrt(50) where A is an integer

Bryan P. avatarAnswered by Bryan P.