Answers>Maths>A Level>Article

The numbers a, b, c and d satisfy the following equations: a + b + 3c + 4d = k; 5a = 3b = 2c = d. What is the smallest value for k for which a, b, c and d are all positive integers

  1. 5a = 3b = 2c = d. d must be a multiple of 5, 3 and 2, therefore the smallest possible value for d is 30. This sets a = 6, b = 10 and c = 152) a + b + 3c + 4d = 6 + 10 + 3x15 + 4x30 = 181 k = 181
MH

Related Maths A Level answers

All answers ▸

Solve the differential equation dx/dt=-6*x , given when t=0 x=7.

Lucy C. avatarAnswered by Lucy C.

Solve the simultaneous equations y = x^2 - 6x and 2y + x - 6 = 0

Tabi D. avatarAnswered by Tabi D.

When do you use integration by parts?

Alex B. avatarAnswered by Alex B.

Differentiate y=(sin(x))^(2)

Bill H. avatarAnswered by Bill H.