In triangle ABC, right angled at B, AB = 3 cm and AC = 6 cm. Determine angle BAC and angle ACB.
Using the trignometric principles,sin (ACB) = AB/AC = 3/6 = 1/2Thus, angle ACB = 30 degreesand angle BAC = 90 - angle ACB = 60 degrees
PS
Using the trignometric principles,sin (ACB) = AB/AC = 3/6 = 1/2Thus, angle ACB = 30 degreesand angle BAC = 90 - angle ACB = 60 degrees
