Differentiate this equation: xy^2 = sin(3x) + y/x

y2 + 2xy dy/dx = 3cos(3x) + 1/y - x/y2 dy/dx                   thereforedy/dx = (3cos(3x) + 1/y - y2​​​​​​) / (2xy + x/y2)

Answered by Alexander E. Maths tutor

3331 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Express 1/((x^2)(1-3x) in partial fractions.


How do you differentiate x^x?


Integrate 5(x + 2)/(x + 1)(x + 6) with respect to x


How do I work out what integration method I should use to solve an integral?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences