From what height, h, should a rail-cart fall to complete a loop-the-loop of radius r without falling off a the track? Assume the track on which the rail-cart travels is smooth and express h in terms of r.

This question combines the principles of energy conservation and circular motion. The insight is to realise the condition for which the rail-cart will fall off of the track - when there is no contact force between the cart and track at the apex of the loop.Energy of cart at top of track: mgh Energy of cart at apex of loop: mg(2r) + 0.5mv2Hence energy conservation implies that mgh = mg(2r)Newton's Second Law at apex of the loop: Fcentripetal = mv2/r = mg - FcontactSetting Fcontact = 0 and substituting v2 = g into energy conservation equation gives h = 2.5r

BR

Related Physics A Level answers

All answers ▸

The mercury atoms in a fluorescent tube are excited and then emit photons in the ultraviolet region of the elecrtomagnetic spectrum. Explain how the mercury atoms become excited.


Explain what simple harmonic motion means?


Show that the radius of an orbit may be expressed as follows: R^3=((GM)/4*pi^2)T^2


Explain the findings from Rutherford's alpha particle scattering experiment.