From what height, h, should a rail-cart fall to complete a loop-the-loop of radius r without falling off a the track? Assume the track on which the rail-cart travels is smooth and express h in terms of r.

This question combines the principles of energy conservation and circular motion. The insight is to realise the condition for which the rail-cart will fall off of the track - when there is no contact force between the cart and track at the apex of the loop.Energy of cart at top of track: mgh Energy of cart at apex of loop: mg(2r) + 0.5mv2Hence energy conservation implies that mgh = mg(2r)Newton's Second Law at apex of the loop: Fcentripetal = mv2/r = mg - FcontactSetting Fcontact = 0 and substituting v2 = g into energy conservation equation gives h = 2.5r

Answered by Benjamin R. Physics tutor

1107 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

How could I calculate the internal resistance of a cell?


Explain why for heavy nuclei there is imbalance in the number of protons and neutrons. Give reference to the range and particle type of the forces that influence this imbalance.


How to we work out the speed of an object at a certain point in its trajectory?


Light with a frequency of 200nm is shone on a sodium plate with a work function of 2.28eV and electrons start escaping the surface of the plate due to the photoelectric effect. What is the maximum kinetic energy of one of these electrons in eV?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences