From what height, h, should a rail-cart fall to complete a loop-the-loop of radius r without falling off a the track? Assume the track on which the rail-cart travels is smooth and express h in terms of r.

This question combines the principles of energy conservation and circular motion. The insight is to realise the condition for which the rail-cart will fall off of the track - when there is no contact force between the cart and track at the apex of the loop.Energy of cart at top of track: mgh Energy of cart at apex of loop: mg(2r) + 0.5mv2Hence energy conservation implies that mgh = mg(2r)Newton's Second Law at apex of the loop: Fcentripetal = mv2/r = mg - FcontactSetting Fcontact = 0 and substituting v2 = g into energy conservation equation gives h = 2.5r

BR
Answered by Benjamin R. Physics tutor

1584 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

What do you understand by simple harmonic motion?


A model truck A of mass 1.2 kg is travelling due west with a speed of 0.90 m/s . A second truck B of mass 4.0 kg is travelling due east towards A with a speed of 0.35 m/s .


What are the SUVAT equations and how can I remember them?


A Uranium-(238,92) nucleus decays into a Thorium-234 nucleus by the emission of an alpha-particle. Given Thorium has a chemical symbol Th build a nuclear equation.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning