Given the following system of linear equations x - 3y = 5 AND 2x + y = 3 how do I find x and y?

To solve this system of linear equations (therefore, to find x and y) we can proceed the following:1) we isolate x from the first question, moving -3y on the right hand side of the equation. When we move 3y on the other side of the equation, remember to change the sign. We get: x = 3y + 53) Now that we have x, we can substitute 'x' with 3y + 5 in the second equation. When you do so, remember to keep the parenthesis. We get: 2(3y + 5) + y = 3.4) Now we need to isolate the y from the equation in point 3. We proceed in the following way: 6y + 10 + y = 3 7y + 10 = 3 7y = 3 - 10 7y = -7 y = 7 / (-7) y = -15) now that we have found y, we only need to substitute y into the first equation of the system and we will be able to find x: x - 3 (-1) = 5 x + 3 = 5 X = 5-3X =2