Given that y= x^(-3/2) + (1/2)x^4 + 2, Find: (a) the integral of y (b) the second differential of y

This is a typical question for a Core 1 paper. (a) integral of y = (-2)x^(-1/2) + 0.1x^5 + 2x +C Method: Increase the power of x by +1, divide the term through by the new power. (b) dy/dx = (-3/2)x^(-5/2) + 2x^3 + 2 d2y/dx2 = (15/4)x^(-7/2) + 6x^2 Method: Multiply the coefficient of x by its power, then reduce the power of x by 1. This process is completed twice in order to reach the second differential.

Related Maths A Level answers

All answers ▸

Integration of ln(x)


Why do you get e^x when you differentiate e^x


How do I find the equation of the normal to the curve y=x^2 at the point (x1,y1)? Where x1=2 and y1=4 .


How can I improve my mathematics


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences