Describe the process of oxygen transport via haemoglobin.

Haemoglobin is a complex metal ion consisting of hexa-coordinated Fe2+ ions. With 6 coordinate bonds, haemoglobin forms an octahedral shape where 4 nitrogen ligands form a haem disc, a globin molecule forms the 5th bond, and the final bond can be interchanged between H2O and O2. An equilibrium is established by this 6th bond, following the equation: Hb(H2O)4 + 4O2 <=> Hb(O4) + 4H2O. In the lungs, oxygen concentration is higher, or increased, so equilibrium shifts right to oppose the change, meaning the H2O ligands are substituted for O2 ligands to form oxyhaemoglobin to carry oxygen through the blood. As the oxyhaemoglobin arrives at respiring tissues, oxygen concentration is low, while water concentration is higher due to respiration. Equilibrium shifts left to oppose the change, and oxygen is exchanged with water molecules. When haemoglobin reaches the lungs again, the process repeats.

Related Chemistry A Level answers

All answers ▸

Which chemical would have a higher boiling point 1,3-dimethylbutane or hexane


State in terms of its bonding why benzene is more stable than cyclohexa-1,3,5-triene:


How do I calculate the Gibbs free energy change for a reaction when given the entropy change, enthalpy change and the reaction conditions>


Write an equation for the incomplete combustion of dodecane to produce gaseous products only.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences