Differentiate sin(2x)/x^2 w.r.t. x

Quotient Rule:d(u/v)/dx = (vu' - uv')/(v2)u = sin(2x) => u' = 2cos(2x)v = x2 => v' = 2x=> (2x2cos(2x) - 2xsin(2x))/(x4)Product Rule:d(uv)/dx = vu' + uv'u = sin(2x) => u' = 2cos(2x)v = 1/x2 = x-2 => v' = -2x-3=> 2x-2cos(2x) - 2x-3sin(2x)

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Answered by Vinh L. Maths tutor

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