A curve C has equation y = x^2 − 2x − 24 x^(1/2), x > 0. Find dy/dx and d^2y/dx^2. Verify that C has a stationary point when x = 4

Using the differentiation rule that d (Ax^b)/dx = Abx^(b-1) we find dy/dx = 2x -2 -12x^(-1/2).Similarly, taking care to see that the -2 term becomes zero since it is not dependent on x, we haved^2y/dx^2 = 2 + 6x^(-3/2).By substituting the value x = 4 into our expression of dy/dx we have2x4 -2 -12x(4^(-1/2)) = 0. Hence we have a stationary point at the value x = 4.

Related Further Mathematics A Level answers

All answers ▸

Find the eigenvalues and eigenvectors of the following 3x3 matrix (reading left to right, top to bottom): (1 0 2 3 1 1 2 0 1)


How can I find the explicit formula for the inverse of sinh?


It is given that z = 3i(7-i)(i+1). Show that z can be written in the form 24i - k. State the integer k.


Given M = [[-2,6],[1,3]], find P and D such that M = PDP^(-1) where D is a diagonal matrix


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences