The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a.

Draw a diagramRearrange the given equation into the form y = mx + cy = -3/2x+7/2Gradients of perpendicular lines - m1*m2=-1, so gradient of PQ = 2/3PQ : y=mx+c -> 4=(2/3)*3+cc=2, therefore PQ: y=2/3x+2 b=2/3a+2 since (a,b) lies on PQ

Answered by Jack W. Maths tutor

2513 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve a simultaneous equation like this: 2x-5y=3, 3x+2y=14 ?


Work out: 20% of 12000


Find the two points of intersection of the graphs y=x2 and y=x+2.


A (0,2) and B (6,5) are points on the straight line ABCD. AB=BC=CD. Work out the co-ordinates of D.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences