Simplify 3/(x+1) + (3x-9)/2 = 1, to get a quadratic equation in the format ax^2 + bx + c = 0.
First, add the two fractions together. The common denominator is 2(x+1), or 2x+2. The first fraction becomes 6/(2x+2). The second fraction becomes (x+1)(3x-9)/(2x+2), or (3x2-6x -9)/(2x+2). Added together, the combined fraction is (3x2-6x-3)/(2x+2).Then, cross multiply to get rid of the fraction. Multiply both sides of the equation by 2x+2. The new equation is: 3x2 - 6x - 3 = 2x + 2.Finally, subtract 2x+2 from each side of the equation to make the right-hand side equal 0, like the questions asks.This gives: 3x2 - 8x - 5 = 0, which is the answer.
