For what values of x is Cosh^2(x) - Sinh(x) = 5 Give your answer in the form of a logarithm

Substitute Cosh^2(x) = 1 + Sinh^2(x) into the starting equation (This formula should be known)Make 0 the subject 3Sinh^2(x) - Sinh(x) - 2 = 0Substitute u = Sinh(x) and solve for uSubstitute Sinh(x) back in followed by Sinh(x) = (e^x - e^-x)/2 (This formula should be known)Rearrange and form an equation in e^2x and e^x where 0 is the subject of one sideSubstitute u = e^x and solve for uSubstitute e^x back in and take the natural log of each side only taking ln(p) such that p>=1 Finish by writing the chosen answers clearly