The gradient of a curve is given by dy/dx = 6sqrt(x) + 2. The curve passes through the point (16, 38). Find the equation of the curve.

dy/dx = 6x1/2 + 2 y = (62/3)x3/2 + 2x + c = 4x3/2 + 2x + c 38 = (4163/2) + (2*16) + c c = 38 - 256 - 32 = -250 y = 4x3/2 + 2x - 250

Answered by Fraser W. Maths tutor

4364 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate ∫sin²xcosxdx


Solve to find sin x , 4cos^2 + 7sin x -7 =0


Find the general solution to the differential equation '' (x^2 + 3x - 1) dy/dx = (2x + 3)y ''


Differentiate the following: 3/2 x^(3/4) + 1/3 x^(-1/4)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences