The gradient of a curve is given by dy/dx = 6sqrt(x) + 2. The curve passes through the point (16, 38). Find the equation of the curve.

dy/dx = 6x1/2 + 2 y = (62/3)x3/2 + 2x + c = 4x3/2 + 2x + c 38 = (4163/2) + (2*16) + c c = 38 - 256 - 32 = -250 y = 4x3/2 + 2x - 250

FW
Answered by Fraser W. Maths tutor

5209 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)


Let y=arcsin(x-1), 0<=x<=2 (where <= means less than or equal to). Find x in terms of y, and show that dx/dy=cos(y).


Write cosx - 3sinx in the form Rcos(x + a)


How do I maximise/minimise a given function f(x)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning