Answers>Maths>IB>Article

Solve for x in the following equation: e^x + 10e^(-x) = 7

First of all, we bring the 7 to the left side of the equation to get: ex-7+10e-x=0. Then, by multiplying both sides of the equation by ex, we can get an equation in the form of a quadratic equation: e2x-7ex+10=0. By setting y = ex, the quadratic nature of the equation can be seen as it simplifies to y2-7y+10=0. From GCSE maths, we know this can be factorised to obtain (y-5)(y-2)=0 and see that y=2 or y=5. The final step for this question is to sub ex back into the equation and solve for x using the ln laws: ex = 2 or 5; therefore x = ln2 or ln5.

Answered by Leonardo B. Maths tutor

3651 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

Find the coordinates that correspond to the maximum point of the following equation: y = −16x^2 + 160x - 256


How to integrate ∫〖3x/√(1-x^2 ) dx〗?


How to I solve system of simultaneous equations (3x3)?


Can you explain the approach to solving IB maths induction questions?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences