An industry is producing copper sulphate (CuSO4) from copper carbonate (CuCO3) and sulphuric acid (H2SO4). The company calculated that from 800 g of CuCO3 they will produce 1kg of CuSO4. However they only produced 900g. What is the percentage yield ?

The percentage yield is calculated in the following way: (Actual yield/Theoretical yield)*100 Here, the actual yield is 900g and the theoretical yield that the company calculated is 1kg. First , we have to convert the units of kg to g to be able to calculate.1kg=1000g Therefore, the percentage yield is: (900/1000)*100=90%

Answered by Dora L. Chemistry tutor

1894 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Can you describe ionic bonding and structure of ionic compounds to me?


If an element has an atomic mass of 19 and a proton number of 9, how many neutrons does it have and how many electrons does it have?


How would you prove that a substance contains magnesium ions?


Why is water less dense in its solid state?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences