If (x+8)^2 - 62 = ax^2 + bx + c, find values a, b and c

Following the rules of BIDMAS, we know that the first action we take to solving this expression is expanding the brackets. To do this we must remember that (x+8)2 does not mean (x)2 + (8)2 but actually means (x+8)(x+8) where all values are multiplied by each other once. So, (x+8)2 = x2 + 8x + 8x + 64 which simplifies to x2 + 16x + 64. Now that we have expanded the brackets we can return to the rest of the expression: (x2 + 16x + 64) - 62 and this gives x2 + 16x + 2.x2 + 16x + 2= ax2 + bx + c, so a= 1 b=16 and c=2

Answered by Teni B. Maths tutor

3200 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A cuboid has dimensions: width = x+1, length = 2x-2, height = x+2. Work out the volume of this cuboid. Give your answer in terms of x.


What actully is the derivative of a function? What does it represent?


Differentiate (2a+3)^5/2 with respect to a


Five numbers have a mean of 9.4 . Four of the numbers are 3, 5, 10 and 12. Work out the range of the five numbers. ( 4 marks )


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences