Solve (2x^2 - 3x - 14)/(x^2 + 6x + 8) = -6/(x+3).

LHS: Factorise numerator and denominator, which gives:((2x - 7)(x + 2))/((x + 2)(x + 4))Cancel out (x + 2), gives:(2x - 7)/(x + 4)Multiply both sides by (x + 4)(x + 3) to cancel the denominators, gives:(2x - 7)(x + 3) = -6(x + 4)Expanding brackets:2x^2 - x - 21 = -6x - 24Make RHS = 0:2x^2 + 5x + 3 = 0Solve with factorisation/complete the square/quadratic formula:(2x + 3)(x + 1) = 0x = -2/3, -1

Answered by Joseph L. Maths tutor

2725 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that multiplication of two odd numbers produces an odd number.


How can I use the Pythagoras' Theorem to work out the length of a missing side of a triangle?


How do I use trigonometric ratios to work out lengths in right-angled triangles?


Jake has a piece of string that is 126cm long. He cuts the string into 3 lengths with the ratio 4:3:2 . How long is each piece of string?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences