make into a cartesian equation= x=ln(t+3) y= 1/t+5

e^x= t+3 t= e^x -3therefore y= 1/e^x-3+5y= 1/e^x+2

Answered by Ryan P. Maths tutor

4330 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Determine the tangent to the curve y = sin^2(x)/x at the point, x = pi/2. Leave your answer in the form ax+by+c=0


The equation of a curve is xy^2= x^2 +1. Find dx/dy in terms of x and y, and hence find the coordinates of the stationary points on the curve.


How would you show that a vector is normal to a plane in 3D space?


How do I plot y=x^2-1?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences