The graph of y = x^2 + 4x - 3 (Graph A) is translated by the vector (3 | 2), find the equation of the new graph (Graph B)

Minimum point of Graph A:*complete square to find(x+2)^2 - 4 - 3 = 0(x+2)^2 - 7 = 0Therefore minimum point = (-2, -7)Minimum point of Graph B:(-2+3, -7+2) = (1, -5)*reverse complete the square method(x-1)^2 - 5 = 0(x-1)^2 - 1 - 4 = 0Therefore equation of Graph B :y = x^2 - 2x - 4