A curve has an equation of y=2x^2 + 7x -8 . Find the co-ordinates of the turning point

Student will need to understand that the turning point will be a minimum as the curve is positiveStudent should complete the square:1) factorise out the 2: 2(x2 + 7/2 x) - 82) complete the square : 2[(x+7/4)2 - (7/4)2] -8 3) the student should square 7/4 to get: 2[(x+7/4)2 - 49/16] -84) multiply the 49/16 by 2: 2(x+7/4)2- 49/8 -84) 2(x+7/4)2 - 113/8 Therefore the co ordinates are (-7/4 , -113/8)

FH
Answered by Farah H. Maths tutor

2907 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There is a spinner game at a fair. The spinner is numbered with all even numbers from 2 to 12. Each section is equal in size. Dan has numbers 4 and 10. What is the probability that he wins a prize? Give your answer as a fraction in its simplest form.


Given the curve y=x^2 -6x +8, find the turning point.


Given the curve y=x^2 +1 and the line y=k, find, using graphical methods only, the value of k for which there is exactly one solution.


Simplify p^2×p^5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences