The function f(x)=x^2 -2x -24x^(1/2) has one stationary point. Find the value of x when f(x) is stationary, and hence determine the nature of this stationary point.
dy/dx = 2x - 2 -12x-1/2dy/dx = 02x - 2 - 12x-1/2 = 0x = 4 (stationary point)d2y/dx2= 2 + 6x-3/2when x=4, d2y/dx2= 11/411/4 > 0 therefore the point is a minimum
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