Solve the simultaneous equations 4x + 7y = 1 and 3x +10y = 15.

There are two main ways of solving this equation, substitution and elimination, here we go through the susbtitution method. This involves rearranging one of the equations to get one of the variables in terms of the other, for example x in terms of y. We then substitute this new expression for x into the other equation and rearrange to solve for y. We then use the value of y in either equation to solve for x.

Rearrange the first equation for x:

4x = 1 - 7y

x = (1-7y)/4

Subsitute x into the second equation:

3*((1-7y)/4) + 10y = 15

Expand the brackets:

(3/4)*(1-7y) + 10y = 15

3/4 -21y/4 + 10y = 15

Collect like terms (write 10y as 40y/4 and 15 as 60/4):

40y/4 - 21y/4 = 60/4 - 3/4

19y/4 = 57/4

Multiply by 4:

19y = 57

Rearrange for y:

y = 57/19 = 3

Subsitute y = 3 into either equation, we use the second:

3x +10*3 = 15

3x + 30 = 15

3x = 15 - 30

3x = -15

x = -15/3 = -5

Finally write the answers out:

x = -5 and y = 3.

LC
Answered by Luke C. Maths tutor

16744 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The work in an office takes 200 hours to complete every week. Each person in the office works 35 hours a week. What is the smallest number of people needed to complete the work?


Expand and Simplify: 16=(x-3)(x+3)


Find the coordinates where the curve y=x^2+6x+5 crosses the x-axis.


A is the point with coordinates (5, 9). B is the point with coordinates (d, 15). The gradient of the line AB is 3. Work out the value of d.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning