A-level: solve 8cos^2(x)+6sin(x)-6=3 for 0<x<2(pi)

8(1-sin^2(x))+6sin(x)-6=38(1-sin^2(x))+6sin(x)-9=08sin^2(x)-6sin(x)+1=0(2sin(x)-1)(4sin(x)-1)=02sin(x)-1=0 4sin(x)-1=02sin(x)=1 4sin(x)=1sin(x)=1/2 sin(x)=1/4x=(pi)/6 , 5(pi)/6 , 0.253 , 2.89

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Answered by Katie M. Maths tutor

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