A-level: solve 8cos^2(x)+6sin(x)-6=3 for 0<x<2(pi)

8(1-sin^2(x))+6sin(x)-6=38(1-sin^2(x))+6sin(x)-9=08sin^2(x)-6sin(x)+1=0(2sin(x)-1)(4sin(x)-1)=02sin(x)-1=0 4sin(x)-1=02sin(x)=1 4sin(x)=1sin(x)=1/2 sin(x)=1/4x=(pi)/6 , 5(pi)/6 , 0.253 , 2.89

KM

Related Maths A Level answers

All answers ▸

Find the integral of x^2e^x


Use integration by parts to find ∫x e^(x)


Why does 'x' need to be in radians to differentiate 'sin x'?


A cubic polynomial has the form p(z)=z^3+bz^2+cz+d, z is Complex and b, c, d are Real. Given that a solution of p(z)=0 is z1=3-2i and that p(-2)=0, find the values of b, c and d.